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Early-transition-metal ketenimine complexes: Synthesis, reactivity, and structure of ketenimine-containing titanocene and zirconocene complexes

机译:早期过渡金属酮亚胺配合物:含酮亚胺的钛茂和锆茂复合物的合成,反应性和结构

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摘要

Reaction of Cp2M(PMe3)(2) complexes (M = Ti, Zr; Cp = eta(5)-C5H5) with the N-(p-tolyl)-diphenylketenimine Ph'N=C=CPh2 (Ph' = p-MeC6H4) in a 1:1 molar ratio affords the ketenimine-containing metallocene derivatives Cp2M(eta(2)-(C,N)-Ph'N=C=CPh2)(PMe3) (M = Ti (1); Zr (2)). The ketenimine ligand reacts in the same way with the ''Cp*M-2'' species (Cp* = eta(5)-C5Me5) generated from the reduction of the corresponding Cp*2MCl2 complexes with (LiBu)-Bu-t (1:2 molar ratio) to give the related complexes Cp*M-2(eta(2)-(C,N)-Ph'N=C=CPh2) (M = Ti (3); Zr (4)). The molecular structure of 3 shows a titanium atom bonded to two eta(5)-cyclopentadienyl rings and a eta(2)-(C,N)-bonded ketenimine ligand. Reaction of ''Cp*Ti-2'' with the ketenimine ligand in a 1:2 molar ratio gives 1,1,5,5-tetraphenyl-3-(p-tolyl)-2-(p-toluidino)-3-aza-1,4-pentadiene, which probably results from the coupling, followed by hydrolysis, of two ketenimine molecules coordinated to one titanocene moiety. Protonation of 3 with Et3NHCl or H2O (1:1 molar ratio) affords the intermediate species Cp*Ti-2(X)(eta(2)-(C,N)-Ph'N=C(H)=CPh2) (X = Cl (5); OH (6)), which on hydrolysis evolves to give the enamine Ph'N(H)-CH=CPh2 as the final product. Finally, 3 reacts reversibly with H-2 to give the hydride enamidate complex Cp*Ti-2(H)(eta(1)-Ph'N-CH=CPh2) (7). The structures of the different compounds have been determined by IR and NMR spectroscopic methods.
机译:Cp2M(PMe3)(2)配合物(M = Ti,Zr; Cp = eta(5)-C5H5)与N-(对甲苯基)-二苯基酮亚胺的反应Ph'N = C = CPh2(Ph'= p-摩尔比为1:1的MeC6H4得到含酮亚胺的茂金属衍生物Cp2M(eta(2)-(C,N)-Ph'N = C = CPh2)(PMe3)(M = Ti(1); Zr( 2))。酮亚胺配体以相同的方式与通过(LiBu)-Bu-t还原相应Cp * 2MCl2复合物而产生的``Cp * M-2''物种(Cp * = eta(5)-C5Me5)反应(1:2摩尔比)得到相关的络合物Cp * M-2(eta(2)-(C,N)-Ph'N = C = CPh2)(M = Ti(3); Zr(4)) 。 3的分子结构显示钛原子键合到两个eta(5)-环戊二烯基环和eta(2)-(C,N)键合的酮亚胺配体。 ``Cp * Ti-2''与酮亚胺配体以1:2摩尔比反应生成1,1,5,5-四苯基-3-(对甲苯基)-2-(对甲苯基)-3 -氮杂-1,4-戊二烯,这可能是由于与一个钛茂部分配位的两个酮亚胺分子偶联,然后水解所致。用Et3NHCl或H2O(1:1摩尔比)使3质子化,得到中间体Cp * Ti-2(X)(eta(2)-(C,N)-Ph'N = C(H)= CPh2)( X = Cl(5); OH(6)),其在水解时会生成最终的烯胺Ph'N(H)-CH = CPh2。最后,3与H-2可逆反应,得到氢化物en酸酯复合物Cp * Ti-2(H)(eta(1)-Ph'N-CH = CPh2)(7)。不同化合物的结构已经通过IR和NMR光谱法确定。

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